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The differential form of the plug flow reactor design equation is ______(a) FA0\(\frac{dX}{dV}\) = -rA(b) \(\frac{dX}{dV}\) = -rA(c) V\(\frac{dX}{dV}\) = -rA(d) \(\frac{dX}{dV}\) = -rA FA0The question was posed to me in an online interview.My question is taken from Design Equations for Flow Reactors in section Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering |
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Answer» Right OPTION is (a) FA0\(\FRAC{DX}{dV}\) = -rA |
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