InterviewSolution
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InterviewSolution
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Calculate the volume of hydrogen librated at N.T.P. when `500 cm^(3)` of `0.5 N` sulphuric acid react with excess of zinc. |
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Answer» Correct Answer - `2800 cm^(3)` Step I. Mass of sulphuric acid in solution `"Normality" (N) = (("Mass of" H_(2)SO_(4))/("Equivalent mass"))/(("Volume of solution in" cm^(3))/(100))` or `(0.5 "equiv" dm^(-3)) = (W)/(((49 "equiv"^(-1)))/((0.5 dm^(3))))` `W = (0.5 "equiv" dm^(-3)) xx (49 g "equiv"^(-1)) xx (0.5 dm^(3)) = 12.25 g`. Step II. Volume of hydrogen liberarted at N.T.P. The chemical equation for the reaction is : `{:(Zn+H_(2)SO_(4),rarrZnSO_(4)+,H_(2)),(2+32+64,,22400cm^(3)),(=98g,,):}` `98g` of `H_(2)SO_(4)` evolve `H_(2)` at N.T.P. `22400 cm^(3)` `12.25 g` of `H_(2)SO_(4)` evolve `H_(2)` at N.T.P. `= 22400 (cm^(3)) xx ((12.25 g))/((98g)) = 2800 cm^(3)` |
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