Calculate the volume of N2 required to produce 44.8 L of NO at STP.

1.	Calculate the volume of N2 required to produce 44.8 L of NO at STP.
Answer» Please MARK me brainliest The reaction is: N₂ + O₂ → 2NO one mole of N₂ and one mole of O₂ GAS REACT to FORM 2 moles of NO gas There are 22.4 litres of N₂ in one mole of the gas and it is also the same for O₂ gas 2 mole of NO will have 2 X 22.4 = 44.8 litres of NO is formed So, 22.4 litres of N₂ and 22.4 litres of O₂ react to form 44.8 litres of NO Hence your answer is 22.4 litres of N₂

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The reaction is:

N₂ + O₂ → 2NO

one mole of N₂ and one mole of O₂ GAS REACT to FORM 2 moles of NO gas

There are 22.4 litres of N₂ in one mole of the gas

and it is also the same for O₂ gas

2 mole of NO will have 2 X 22.4 = 44.8 litres of NO is formed

So, 22.4 litres of N₂ and 22.4 litres of O₂ react to form 44.8 litres of NO

Hence your answer is 22.4 litres of N₂

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