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Calculate the volume of `O_(2)` and volume of air needed for combustion of `1 kg` carbon at `STP`.A. 9333.3 litreB. 933.33 litreC. 93.33 litreD. 1866.67 litre |
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Answer» Correct Answer - A `C + O_(2) to co_(2) ` 1000g `(1000)/(2)` mole `n_(O)_(2)` req. `=(1000)/(2)` mole `air _(req). = (1000)/(12)xx(1)/(0.21)` mole `(1000)(12xx0.21)xx22.4L` =8888.8 L |
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