Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.

Calculate the volume of one mole of any gas at STP and at room tempera

1.	Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.
Answer» Solution :Here STP means standard temperature (T = 273 K or `0^(@)C`) and Pressure (P = 1 atm or 101.3 KPA) We can use ideal gas equation `V=(muRT)/(P)` Here `mu=1` mol and R = 8.314 J/mol.K By SUBSTITUTING the value `V=("(1 mol)"(8.314(J)/(mol)K)(273K))/(1.013xx10^(5)Nm^(-2))=22.4xx10^(-3)m^(3)` We know that 1 Litre `(L)=10^(-3)m^(3)`. So we can conclude that 1 MOLE of any ideal gas hasvolume 22.4 L By multiplying 22.4 by `(300K)/(273K)` we get the volume of one mole of gas at room temperature. It is 24.6 L