Calculate the volume of Oxygen gas at 17°C and 800 torr that may be o

1.	Calculate the volume of Oxygen gas at 17°C and 800 torr that may be obtained by complete decomposition of 50.5 g of KNO3. (Atomic mass; K = 39, N =14, O = 16) (8) 2KNO3 = 2KNO2 + O2
Answer» Answer: Answer Correct option is B 101 g S+O 2 ⟶SO 2 MOLES of S = 32g/mol 16g =0.5 mol 0.5 mol of S requires 0.5 mol of oxygen. So, we know that sulphur burns in 0.5 mol oxygen. The thermal decomposition of Pottasium nitrate: 2KNO 3 ⟶2KNO 2 +O 2 1 mol of O 2 is produced by 2 mol of KNO 3 0.5mol of O 2 will be produced by 1 mol of KNO 3 Thus, 1 mole of KNO 3 is REQUIRED to produce the given amount of oxygen. 1 mol of KNO 3 = molar mass of KNO 3 =101 g Hence, option B is correct

Calculate the volume of Oxygen gas at 17°C and 800 torr that may be obtained by complete decomposition of 50.5 g of KNO3. (Atomic mass; K = 39, N =14, O = 16) (8) 2KNO3 = 2KNO2 + O2

Answer»

Answer:

Answer

Correct option is

101 g

S+O

⟶SO

MOLES of S =

32g/mol

16g

=0.5 mol

0.5 mol of S requires 0.5 mol of oxygen.

So, we know that sulphur burns in 0.5 mol oxygen.

The thermal decomposition of Pottasium nitrate:

2KNO

⟶2KNO

1 mol of O

is produced by 2 mol of KNO

0.5mol of O

will be produced by 1 mol of KNO

Thus, 1 mole of KNO

is REQUIRED to produce the given amount of oxygen.

1 mol of KNO

= molar mass of KNO

=101 g

Hence, option B is correct