Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (K_(sp)of PbCl_(2) = 3.2 xx 10^(-8), atomic mass of Pb = 207 u).

Calculate the volume of water required to dissolve 0.1 g lead (II) chl

1.	Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (K_(sp)of PbCl_(2) = 3.2 xx 10^(-8), atomic mass of Pb = 207 u).
Answer» Solution :Suppose the solubility of `PbCl_(2)` in water is S MOL `L^(-1) `. Then `{:(PbCl_(2)(s)hArrPb^(2+)(aq)+2Cl^(-)(aq)),(""S"" 2S):}` `K_(sp)=(S)(2S)^(2)=4S^(3) = 3.2 xx 10^(-8) ` (Given) or `S^(3) = 0.8 xx 10^(-8) = 8xx10^(-9) or S = 2 xx 10^(-3) "mol" L^(-1)` Molar MASS of`PbCl_(2) = 207 + 71 = 278` `:. ` Solubility of `PbCl_(2)` dissolve in 1 L of water to makea saturated solution. HENCE, water required to dissolve 0.1 g of `PbCl_(2) = (1L)/(0.556g) xx 0.1 g = 0.1798 L = 179.8 mL `.