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Calculate the volume strength of a 3% solution of H_(2)O_(2) |
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Answer» Solution :Step 1. To calculate the amount of `H_(2)O_(2)` present in one litre of 3% solution. 100 mL of `H_(2)O_(2)` solution contain `H_(2)O_(2)` =3g `THEREFORE ` 1000 mL of `H_(2)O_(2)` solution will contain `H_(2)O_(2)=(3)/(100)xx1000=30g` Step 2. To calculate the volume strength Consider the chemical equation, `underset(2xx34=68 g)(2H_(2)O_(2))to 2H_(2)O + underset(22.4 "LITRES at N.T.P.")(O_(2))` Now 68 g of `H_(2)O_(2)` give `O_(2)` at N.T.P. =22.4 litres `therefore `30 g of `H_(2)O_(2)` will give `O_(2)` at N.T.P. `=(22.4)/(68)xx30=9.88` litres=9880 mL. But 30 g of `H_(2)O_(2)` are present in 1000 mL of `H_(2)O_(2)`. Hence, 1000 mL of `H_(2)O_(2)` solution gives `O_(2)` at N.T.P. 9880 mL `therefore ` 1 mL of `H_(2)O_(2)` solution will give `O_(2)` at N.T.P`=(9880)/(1000)=9.88` mL. Hence the volume strength of 3% `H_(2)O_(2)` solution =9.88 |
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