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Calculate the wave length of an electron of mass 9.1 xx 10^(-31) kg, moving with a velocity of 2.05 xx 10^(7)ms^(-1). |
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Answer» SOLUTION :Mass of electron, `m = 9.1 xx 10^(-31) kg` v = velocity of electron `= 2.05xx 10^(7) ms^(-1)` h = Plancks constant `= 6.6256 xx 10^(-34) Js.` `lambda =` wave length = ? According to de BROGLIE equation `lambda=(h)/(MV)=(6.625xx10^(-34)kgm^(2)s^(-1))/(9.1xx10^(-31)kgxx2.05xx10^(7)ms^(-1))` The wave length of electron is `3.55 xx 10^(-11) m` |
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