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Calculate the wavelength and energy of the radiation emitted for the electronic transition from fourth orbit to stationary state 1 of He+ ion. RH=1 × 107 m-1Plank's Constant (h) = 6.63 × 10-34 J-s Solution |
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Answer» λ1 = R [ n 12 1 - n 22 1 ]= 109678 CM −1 [ 1 2 1 - ∞ 2 1 ]= 109678 cm −1 λ = 109678cm −1 1 = 9.118 × 10 −6 cmE = λhc = 9.118×10 −8 6.62×10 −34 ×3 = 2.178 × 10 18 J |
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