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Calculate the wavelength of a photon in Angstrom units having energy of one electron volt |
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Answer» Solution :Energy (E) = 1EV = `1.602 XX 10^(-19)J` `h = 6.626 xx 10^(-34) Js, c = 3 xx 10^(8) ms^(-1)` `E = hv = (hc)/(LAMDA)` or `lamda = (hc)/(E) = ((6.626 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/(1.602 xx 10^(-19) J) = 12.42 xx 10^(-7) m` `= 12.42 xx 10^(-7) xx 10^(10) Å = 12.42 xx 10^(3) Å` |
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