1.

Calculate the wavelength of a photon in Angstrom units having energy of one electron volt

Answer»

Solution :Energy (E) = 1EV = `1.602 XX 10^(-19)J`
`h = 6.626 xx 10^(-34) Js, c = 3 xx 10^(8) ms^(-1)`
`E = hv = (hc)/(LAMDA)`
or `lamda = (hc)/(E) = ((6.626 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/(1.602 xx 10^(-19) J) = 12.42 xx 10^(-7) m`
`= 12.42 xx 10^(-7) xx 10^(10) Å = 12.42 xx 10^(3) Å`


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