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Calculate the wavelength of a photon in Angstrons having an energy of 1 electron-volt. |
Answer» Energy of photon ` 1eV=1.602 xx 10^(-19)J` `h=6.626 xx 10^(-34)Js, c=3xx10^(8)ms^(-1)` `E=hv=(hc)/(lambda)` or `lambda= (hc)/(E)` By substituting the values, `" " lambda=((6.626 xx 10^(-34) Js)xx (3xx10^(8)ms^(-1)))/((1.602 xx 10^(-19)J))=12.42 xx 10^(-7)m` `=12.42 xx 10^(-7) xx 10^(10) Ã… or 12.42 xx 10^(3) Ã…`. |
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