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Calculate the wavelength of an electron moving with velocity of 2.05xx10^(7) ms^(-1) |
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Answer» Solution :By de Broglie equation `lambda=h/(mv)=(6.626xx10^(-34) JS)/((9.11xx10^(-31) KG)(2.05xx10^(7) ms^(-1)))=3.55xx10^(-11)m (1 J=1 kg m^(2) s^(-2))` |
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