calculate the wavelength of light required to break the bond between t

1.	calculate the wavelength of light required to break the bond between two Cl atoms in Cl2 molecules.(bond energy of Cl-Cl is 243 kJmol^-1)
Answer» Solution : 1 KJ /MOL = 0.0167 × 10-19 J / molecule 243 KJ /mol = 0.0167 × 243 × 10-19 = 4.067 × 10⁻¹⁹ J /molecule. According to Planck's law, E = HC / λ Therefore, λ = hc / E h - Planck constant = 6.625 × 10⁻³ c - velocity of light = 3 × 10⁸ m/s = (6.625 × 10⁻³ * 3 × 10⁸ m/s ) / ( 4.067 × 10⁻¹⁹ ) = 4.887 * 10⁻⁷ m λ = 488 nm nm - nanometer = 10⁻⁹ m

calculate the wavelength of light required to break the bond between two Cl atoms in Cl2 molecules.(bond energy of Cl-Cl is 243 kJmol^-1)

Answer»

Solution :

1 KJ /MOL = 0.0167 × 10-19 J / molecule

243 KJ /mol = 0.0167 × 243 × 10-19

= 4.067 × 10⁻¹⁹ J /molecule.

According to Planck's law,

E = HC / λ

Therefore,

λ = hc / E

h - Planck constant = 6.625 × 10⁻³

c - velocity of light = 3 × 10⁸ m/s

= (6.625 × 10⁻³ * 3 × 10⁸ m/s ) / ( 4.067 × 10⁻¹⁹ )

= 4.887 * 10⁻⁷ m

λ = 488 nm

nm - nanometer = 10⁻⁹ m