1.

Calculate the wavelength of proton which is accelerated by a potential of 35 volts ( mass of proton = 1.66 multiplied by 10^-27 kg )

Answer»

21 mv 2 KE= 2mp 2 De-broglie WAVELENGTH,λ= PH λ= 2mE h = 2mVe h Putting the values of CONSTANTS, we get:λ= 2×1.6×10 −27 ×1.6×10 −19 ×1000 6.6×10 −34 =0.9×10 −12 m



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