Calculate the weight of calcium calcium carbonate required to produce carbondioxide that is sufficient for conversion of one decimole sodium carbonate to sodium bicarbonate.

Calculate the weight of calcium calcium carbonate required to produce

1.	Calculate the weight of calcium calcium carbonate required to produce carbondioxide that is sufficient for conversion of one decimole sodium carbonate to sodium bicarbonate.
Answer» Solution :Step 1: Regarding the requirement of cabon dioxide: The balanced equation for conversion of sodium carbonate to sodium bicarbonte is `Na_(2)CO_(3)+H_(2)O+CO_(2) to 2NaHCO_(3)` Decimole =0.1 mole 1mole of `Na_(2)CO_(3)="1 mole of "CO_(2)` Carbondioxide required for 0.1 mole of `Na_(2)CO_(3)=` 0.1 mole (or 4.4 grams) Step 2: Regarding the requirement of CALCIUM carbonate. The balanced equaiton for the decomposition of calcium carbonate is `CaCO_(3) to CaO+CO_(2)` 1 mole of `CO_(2)="1 moleof "CaCO_(3)` 14 grams of `CO_(2_)="100 grams of CaCO_(3)` The weight of calcium carbonate to produce the required 4.4 grams carbondioxide `=(100)/(44) xx4.4 =10"gramas"`