Calculate the weight of carbon of monoxide having the same number of oxygen atoms as are present in 88 g of carbon dioxide.

Calculate the weight of carbon of monoxide having the same number of o

1.	Calculate the weight of carbon of monoxide having the same number of oxygen atoms as are present in 88 g of carbon dioxide.
Answer» Solution :Step I. No of OXYGEN ATOMS in 88.0 of `CO_(2)` 44.0 g GRAMS of `CO_(2)` have oxygen atoms `= 2 XX 6.022 xx 10^(23)` `= 4 xx 6.022 xx 10^(23)` Step II. Calculation of mass of CO `6.022 xx 10^(23)` oxygen atoms are present in CO = 28.0 g `4 xx 6.022 xx 10^(23)` oxygen atoms are present in `CO=28.0xx(4xx6.022xx10^(23))/(6.022xx10^(23))=112.0g`.