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Calculate the weight of iron which will be converted into its oxide by the reaction of `18 g` of steam. |
Answer» `underset(3 xx 56)(3 Fe) + underset(4 xx 18)(4 H_(2) O) rarr Fe_(3) O_(4) + 4 H_(2)` `4 xx 18 g "of" H_(2) O = 3 xx 56 "of" Fe` `18g "of" H_(2) O = (3 xx 56)/(4 xx 18) xx 18 = 42 g "of" Fe` |
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