Calculate the weight of methane in a 9.00 litres cylinder at 16 atm an

1.	Calculate the weight of methane in a 9.00 litres cylinder at 16 atm and 27^@C.
Answer» Solution :According to ideal gas equation, `PV = nRT` In the present CASE, `P= 16 " atm, " "" V = 9.00 L, ""T = 273 + 27 = 300 K" and "R = 0.0821 " litre atm " K^(-1)mol^(-1)` `:."" n = (PV)/(RT) =(16 xx 9.00)/(0.0821 xx 300) = 5.85` The gram MOLECULAR mass of methane `(CH_4) = 16` `:.`One mole of `CH_4`weight = 16 g `:.5.85" moles of " CH_4 " will weight " = 16 xx 5.85 = 93.6 g` Hence, the weight of the gas in the given conditions is 93.6 g.

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