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Calculate the weight of zinc required for the liberation of 10 g of hydrogen gas on reaction with `H_(2)SO_(4)`. |
Answer» `{:(Zn+H_(2)SO_(4) toZnSO_(4) +H_(2)),(" 1 mole" " 1 mole"):}` Atomic weight of zinc is ` 65.5` 1 mole of hydrogen = 2 g of hydrogen 10 g of hydrogen = `10/2 = 5` moles 1 mole of `H_(2)` gas is produced from 1 mole of zinc 5 moles of `H_(2)` gas are produced from 5 moles of zinc. 1 mole of zinc = 65.5 g 5 mole of zinc = ` 65.5 xx 5 = 327. 5 ` g |
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