Calculate the work done by the system in an irreversible (sing step) adiabatic expansion of 2 mole of a polyatomic gas (gamma= 4//3) from 300K and pressure 10atm to 1 atm: (in KJ) (Give your answer after multiplying with 2.08).

Calculate the work done by the system in an irreversible (sing step) a

1.	Calculate the work done by the system in an irreversible (sing step) adiabatic expansion of 2 mole of a polyatomic gas (gamma= 4//3) from 300K and pressure 10atm to 1 atm: (in KJ) (Give your answer after multiplying with 2.08).
Answer» `-227R` `-810` Cal `-405R` `-3.367 kJ` Solution :IRREVERSIBLE adiabatic `rArr Delta E=- P_("ext") Delta V` `nC_(V) (T_(2)- T_(1)) = -P_("ext") ((nRT_(2))/(P_(2)) - (nRT_(1))/(P_(1)))` `2 xx 3R(T_(2) - 300) =-1(2R) ((T_(2))/(1) - (300)/(10))` `3(T_(2) - 300) = 30 - T_(2)` `4T_(2) = 930 rArr T_(2) = (930)/(4) = 232.5K` `rArr Delta E= W = n C_(V) Delta T` `=2 xx 3R (232.5 - 300)` = -405R`