Calculate the work done during the reaction represented by the followi

1.	Calculate the work done during the reaction represented by the following thermochemical equation at 300K :CH4 + 2O2 ➡️ CO2 + 2H20(g). (g). (g). (L)(R= 8.314 J/Kmol)
Answer» Work Done COMES 4.988 kJ Explanation: Work is done during any chemical reaction that can be calculated with the HELP of a Chemical EQUATION. The Chemical Equation says - Work Done = $- \Delta n_g \times R \times T$ """(1) where, Where $\Delta$ is the change in the NUMBER of MOLES of gas. $\Delta n_g$ = -(-2) = 2 The Universal gas Constant, R = 8.314 $\frac {J}{Kmol}$ Temperature, T = 300 K Applying Equation (1) we get - W = $- \Delta n_g \times R \times T$ = $-(-2) \times 8.314 \times 300$ = 4988.4 J or 4.9884 kJ is the Work Done