1.

Calculate the work done during the reaction represented by the following thermochemical equation as 300k.CH4 + 2O2 -------> CO2 +2H2O1. +4.988 kg. 2.-4.988 kg. 3.-49.88 kg. 4.+49.88 kg. ​

Answer»

ANSWER:

Explanation:

+4.988kJ

Explanation:

Ch4+2o2=CO2+h2o

Ch4 co2 and O2 are in GASEOUS state so

Delta ng ie no of moles of gaseous product-no of moles of gaseous reactant

=1-3=-2

W=delta ng RT

W=-2×8.314.300

W=4988 J

W=+4.988kJ



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