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Calculate the work done in a resistor of 20 ohm carrying 5A of current in 3 hours.(a) 1.5J(b) 15J(c) 1.5kWh(d) 15kWhI got this question in exam.The above asked question is from Power in division Simple DC Networks of Basic Electrical Engineering

Answer» RIGHT CHOICE is (c) 1.5kWh

Explanation: To find POWER: P=I^2R=5^2*20=500W=0.5kW.

To find WORK done: W=Pt=0.5*3=1.5kWh.


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