1.

Calculate the work done (in J) when 4.5 g of H_(2)O_(2) reacts against a pressure of 1.0 atm at 25^(@)C2H_(2)O_(2)(l)rarr O_(2)(g) +2H_(2)O(l)

Answer»

`-1.63 XX 10^(2)`
`4.5 xx 10^(2)`
`3.2 xx 10^(2)`
`-6.1 xx 10^(2)`

SOLUTION :`w=-Deltan_(g)RT=(-4.5 )/(34xx2)xx8.314 xx298`,
`w=-163.9 J`


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