1.

Calculate the work done when 1.0 mol of water at 373 K vaporizes against an atmospheric pressure of 1.0 atmosphere. Assume ideal gas behaviour.

Answer»


Solution :`PV=nRT` or`V= (nRT)/(P) = (1MOL xx 0.0821 L atmK^(-1) mol^(-1) xx 373 K)/(1ATM) =30.6 L`
Taking volume of LIQUID water to be negligible,`Delta V =V_("VAPOUR") - V_(H_(2)O(l))=30.6 L`.


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