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Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25^@C and normal pressure. |
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Answer» Solution :Given n=2 moles `V_i`=500 ml =0.5 lit `V_f`=2 lit `T=25^@C`=298 K `w=-2.303 nRT LOG (V_f/V_i)` `w=-2.303 xx2xx8.314xx298 xxlog (2/0.5)` w=-2.303 x 2 x 8.314 x 298 x 0.6021 w=-6871 J w=-6.871 kJ |
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