1.

Calculate the work done when1 moleof an ideal gas is compressed reversibly from 1.0 bar to 4.00 bar at constant temperature of 300K

Answer»

`3.46 kJ`
`-8.20 kJ`
`18.02kJ`
`-14.01kJ`

SOLUTION :`W= - 2.303 nRT LOG. (P_(1))/(P_(2))= - 2.303 XX 1 xx 8.314 xx 300 log. (1)/(4) = 3458J = 3.458 kJ`


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