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Calculate the work required to be done to stop a car of 1500 if moving at a speed of 60 km/h? |
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Answer» N VALUES:- m= 1500, U= 60km/hr u= 60X5/18 = 50/3m/s = V=0 SOLUTION:- w = CHANGE in its K.E. initial KE =1/2 mu² final KE=1/2mv²W= final K.E. — initial K. E. = 1/2mv² - 1/2 mu²=1/2m(v²-u²) = 1/2 * 15000{(0)²- (50/3)2} |
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