Calculate the work, when 1 mole ideal gas defuse to 1 atm from 10 atm at 300. K temperature.

Calculate the work, when 1 mole ideal gas defuse to 1 atm from 10 atm

1.	Calculate the work, when 1 mole ideal gas defuse to 1 atm from 10 atm at 300. K temperature.
Answer» 5744.1 J 6257.2 J 4938.8 J 4138.8 J Solution :When isothermal expansion of ideal GAS is done, For isothermal process, `w_("REV") = - 2.303 "nRT" log""(P_1)/(P_2)` where, `n =1` mole ideal gas `R=8.314` Joule KELVIN`""^(-1) "mol"^(-1)` `T= 300K` `P_1=`Initial pressure = 10 atm `P_2=` Final pressure = 1 atm `therefore w_("rev") = - 2.303 (1 "mole") (8.314 "Joule Kelvin"^(-1) "mole"^(-1) ) (300 K) log ""(10)/(1)` `= - 2.303 xx 8.314 xx 300 xx 1` J `= -5744.1` J VALUE of w is -ve. So, work done by system = 5744.1 J