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Calculate thewavenumberfor thelongestwavelengthtransitionin the Balmerseries of atomichydrogen |
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Answer» SOLUTION :ForBalmerseries `n_(i)= 2 ` and ` n_(2)= 3 ,4,5 ` forlongestwavelengthtransitionthe isleast Accordingto balmer `VEC( v) =109677 ((1)/(n_(1)^(2) )-(1)/(n_(2)^(2))) cm^(-1)` `=10967 ((9-4)/(36))` `=109677 ((5)/(36))` `=15232.9 cm^(-1)` `=1.52329 xx 10^(4) cm^(-1)` `=1.52329 xx 10^(6)m^(-1)= 1.523 xx 10^(6) m^(-1)` |
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