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Calculate total number of fundamental particles present in a molecule of heavy water |
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Answer» Solution : In each deuterium atom `(""_1H^2)`, totally THREE FUNDAMENTAL particles `(1e^- , 1p , 1n)`are present. In each oxygen atom `(""_8O^16)`, 24 fundamental particles `(8e^(-) , 8p, 8n)`are present. Total number of fundamental particles in a molecule of heavy WATER `(D_2O) = (2xx 3) + 24 = 30` |
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