Calculate work done to move a boy of mass 20 kg along an inclined plane (theta = 45^(@)) with constent velocity through a distance of 10 m.

Calculate work done to move a boy of mass 20 kg along an inclined plan

1.	Calculate work done to move a boy of mass 20 kg along an inclined plane (theta = 45^(@)) with constent velocity through a distance of 10 m.
Answer» Solution :Here the motion is not accelerated the resultant FORCE parallel to the plane must be zero. So, F = Mg SIN `45^(@) = 0`. Force, F = Mg sin `45^(@)`, distance d = 10 m the workdone. W = Fd COS `theta` `=(Mgsin 45^(@))d cos 0^(@)"" [because theta = 0^(@)" So ", cos 0^(@)=1]` `=20xx10xxsin 45^(@)xx10xx cos 0^(@)` `=20xx10xx(1)/(sqrt(2))xx10xx1=1414J` Workdone, W = 1414 J