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CalculateDeltaU andDeltaH in calories if one moleofa monoatomic ideal gas is heated at constant pressure of 1 atom from 25^(@)C to 50^(@)C

Answer»

Solution :For monoatomic ideal gas ,` C_(v) =(3)/( 2) R,C_(p) =(5)/(2) R`
But `C_(p) =(DeltaH)/( DeltaT)`
`:. DeltaH = C_(p)DeltaT mol^(-1)` ( or `nC_(p)DeltaT ` for nmoles)
`=( 5)/( 2) xx1.987 xx25 = 124.2cal`
Work done , ` w= -P DeltaV= -P(V_(2)-V_(1)) = -(PV_(2)-PV_(1))= - ( nRT_(2) - nRT_(1))= - NR(T_(2)-T_(1)) `
`= -1 xx 1.987 (323 -298 ) cal = -49.7 cal`
` DeltaU = q+w =124.2 - 49.7 cal =74.5 cal`


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