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Calculatedthe molality of a solution containing 7.5 g of glycine(NH_2 -CH_2 -COOH)dissolved in 500g of water |
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Answer» SOLUTION :Molality `= ("No. of moles of solute")/("MASS of solvent (in KG)")` No. of moles of GLYCINE `=("mass of glycine")/("Molar mass of glycine") = (7.5)/(75) =0.1` Molality `= ( 0.1)/(0.5 kg) =0.2 m` |
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