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Calculateenergyof onemoleof photonsofradiationwhosefrequencyis 5xx 10^(14) Hz (h = 6.626 xx 10^(34)j) |
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Answer» Solution :E= hv = (6.626 `xx10^(34)`J s ) `xx (5 xx 10^(14) s^(-1))` 1 molephtonn= 6.626 `xx10^(34) js` E=(6.022 `xx 10^(23)` )(3.313 `xx 10^(19)` J) E = 199. 51 KJ `mol^(-1)` |
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