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Calculatethe energy requiredto convert all theatoms of magnium to magnesium ions present in 24 mg ofmagnesium vapours : First and second ionization enthalpies of Mg are737.76 and1450.73 kJ mol^(1) respectively. |
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Answer» SOLUTION :According to THEDEFINITION of successiveionizationenthalpies. `Mg (g)+ Delta_(i) H_(1)to Mg^(+) (g) + e^(-) (g) ,Delta_(i) H_(1) 737.76 kJ mol^(-1)` `Mg^(+) (g)+ Delta_(i) H_(2) to Mg^(2+)(g) + e^(-) (g),Delta_(i) H_(2)= 1450 .73 kJ mol^(-1)` `:.` Totalamountof energyneededto CONVERT Mg (g)atom into `Mg^(2+) (g) ion = Delta_(i) H_(1) + Delta_(i) H_(2)` `=737.76 + 1450.73 kJ mol^(-1) =m 2188.49 kJ mol^(-1)` 24 mg of mg `=(24)/(1000) g= (24)/(1000xx 24) " mole " = 10^(-3) `mole `:.` Amountof energyneededto ionize`10^(-3)` mole ofMgvapours `=2188.49 xx 10^(-3) =2.188 kJ` |
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