1.

Calculatethe energyrequiredfor theprocess He_(g)^+ to He_(g)^(2+)+ e^(-) theionizationenergyfor the Hatom in thegroundstateis 2.18 xx 10^(-18)J atom^(-1)

Answer»

Solution :Energyof norbitatom for`(H , He^(+) Li^(2+) ` is`E_(N))`
`E_(n) = (2.18 XX 10^(18) Z^(2))/( n^(2)) J atom^(1)`
for HZ-1and n=1
IP`2.18 xx 10^(18) J atom^(-1)`
ionizationof`He^(+)` is`He^(+)to He^(2) + e^(-)`
Hereionizationfor `He^(+)`
`n_(1)1 ` ASND `n_(2)= PROP`z=-2
`Delta E = 2.18xx 10^(18) (2^(2))/(1^(2)) (1)/( 1^(2))- (1)/(prop^(2))`
`=2.18 xx 10^(18) (4)`
ionizationenertgy of `He^(+)`
`=He^(+) to He^(2+)e^(-)`reactionenergy


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