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Calculatethe energyrequiredfor theprocess He_(g)^+ to He_(g)^(2+)+ e^(-) theionizationenergyfor the Hatom in thegroundstateis 2.18 xx 10^(-18)J atom^(-1) |
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Answer» Solution :Energyof norbitatom for`(H , He^(+) Li^(2+) ` is`E_(N))` `E_(n) = (2.18 XX 10^(18) Z^(2))/( n^(2)) J atom^(1)` for HZ-1and n=1 IP`2.18 xx 10^(18) J atom^(-1)` ionizationof`He^(+)` is`He^(+)to He^(2) + e^(-)` Hereionizationfor `He^(+)` `n_(1)1 ` ASND `n_(2)= PROP`z=-2 `Delta E = 2.18xx 10^(18) (2^(2))/(1^(2)) (1)/( 1^(2))- (1)/(prop^(2))` `=2.18 xx 10^(18) (4)` ionizationenertgy of `He^(+)` `=He^(+) to He^(2+)e^(-)`reactionenergy |
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