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Calculatethe force .F. needed to punch a 1.46cm diameter hole in a steel plate 1.27 cm thick (as shown in fig). The ultimate shear strength of steel is 345 M N//m^(2) |
Answer» Solution : As in punching, shearelasticity is involved, the hole will be punched it `((F_(11))/(A)) gt` ultimateshear stress `F_(11) gt ` (SHEAR stress ) X Area `F_(11)` min `=(3.45xx10^(8))(2pi RL)(A=2pirL)` `=(3.45xx10^(8)) (2xx3.14)xx0.73xx10^(-2) xx 1.27 xx 10^(-2)` `=200KN` |
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