Calculatethe force .F. needed to punch a 1.46cm diameter hole in a steel plate 1.27 cm thick (as shown in fig). The ultimate shear strength of steel is 345 M N//m^(2)

Calculatethe force .F. needed to punch a 1.46cm diameter hole in a ste

1.	Calculatethe force .F. needed to punch a 1.46cm diameter hole in a steel plate 1.27 cm thick (as shown in fig). The ultimate shear strength of steel is 345 M N//m^(2)
Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C10_SLV_040_S01.png" width="80%"/> <br/> As in punching, shearelasticity is involved, the hole will be punched it<br/> `((F_(11))/(A)) gt` ultimateshear stress<br/> `F_(11) gt ` (<a href="https://interviewquestions.tuteehub.com/tag/shear-1205062" style="font-weight:bold;" target="_blank" title="Click to know more about SHEAR">SHEAR</a> stress ) <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> Area <br/> `F_(11)` min `=(3.45xx10^(8))(2pi <a href="https://interviewquestions.tuteehub.com/tag/rl-614468" style="font-weight:bold;" target="_blank" title="Click to know more about RL">RL</a>)(A=2pirL)` <br/> `=(3.45xx10^(8)) (2xx3.14)xx0.73xx10^(-2) xx 1.27 xx 10^(-2)` <br/> `=200KN`</body></html>