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| 1. |
Calculatethe totalnumberof degressof freedompossessedby themoleculesin onecm^3 ofH_2gasat NTP . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :22400`cm^2`of <a href="https://interviewquestions.tuteehub.com/tag/every-976721" style="font-weight:bold;" target="_blank" title="Click to know more about EVERY">EVERY</a> gascontains`6.02 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(23)`molecules<br/>` therefore ` Numberof moleculesin `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> cm ^3 ` of ` H_2 ` gas`=( 6.02xx 10^(23))/( 22400 ) = 0.26875xx 10^(20)`<br/>Numberof degreesof freedomof a` H_2` gasmolecule = 5 <br/>` therefore `Totalnumberof <a href="https://interviewquestions.tuteehub.com/tag/degress-436458" style="font-weight:bold;" target="_blank" title="Click to know more about DEGRESS">DEGRESS</a> of freedomof `0.26875xx 10^(20)`molecules<br/> `= 0.26875xx 10^(20) xx 5 = 1.34 375xx 10^(20)`</body></html> | |