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Calculatethe wavelengthof anelectronmovingwith avelocityof 2.05 xx 10 ^(7)ms^(-1) |
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Answer» Solution :ACCORDINGTO de - BROGLIE `lambda = (h)/( mv )` `h= 6.626 xx 10^(34)JS` `v= 2.05 xx 10^(7)ms^(-1)` `m=9.1 xx 10^(31) KG` `=(6.626 xx 10^(34) js)/( (9.1xx 30^(-31) kg )(2.05 xx 10^(7)ms^(-1)))` `=0.3552 xx 10^(10) J s^(2) kg^(-1) m^(-1)` `lambda= 3.552 xx 10^(11)`m= 35.52 pm |
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