Calculating cell constant: Conductivity of a decimolar solution of potassium chloride at `180^(@)C` is `1.12 Sm^(-1)`. The resistance of a conductivity cell containing the solution at `180^(@)C` was found to be `55 ohm`. What is the cell constant. Strategy: Use Equation (3.18) and solve for cell constant.

Calculating cell constant: Conductivity of a decimolar solution of pot

1.	Calculating cell constant: Conductivity of a decimolar solution of potassium chloride at `180^(@)C` is `1.12 Sm^(-1)`. The resistance of a conductivity cell containing the solution at `180^(@)C` was found to be `55 ohm`. What is the cell constant. Strategy: Use Equation (3.18) and solve for cell constant.
Answer» Conductance `(G) = 1//R = (1)/(55) S` Conductance `(K) = 1.12 Sm^(-1)` Substituting these results into Equation (3.18) solving for cell constant, we have cell constant `(l//A) = (K)/(G)` `= (1.22 Sm^(-1))/(1//55)S` `61.6 m^(-1)` `= 0.616 cm^(-1)`

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