Calculation of oxidation state of copper in cupric oxide

1.	Calculation of oxidation state of copper in cupric oxide
Answer» This is too broad a question, you can't memorize its oxidation STATES, per se, but you can rationalize what it is by memorizing the rules for common anions it usually bonds with!Explanation:For instance,CuSO4 — copper (II) sulfatex+(+6)+(−8)=0 We know sulfate's charge is 2-, and we also memorize that an oxide anion has an oxidation state of 2-, unless its a peroxide in which case its charge is 1-, but that's another question!So, SOLVING this 8th grade algebra problem, we get:x−2=0 x=2 THUS, in this particular compound, copper's oxidation state is 2+!

Discussion