Calculte molar conductance at infinite dilution for acetic acid, given `A_(m)^(oo)HCI=425 ohm^(-1)cm^(-1),A_(m)^(oo)NaCI=188 ohm^(-1)cm^(-1),A_(m)^(oo)CH_(3)COOHNa=96 ohm^(-1)cm^(-2)mol^(-1)`

Calculte molar conductance at infinite dilution for acetic acid, given

1.	Calculte molar conductance at infinite dilution for acetic acid, given `A_(m)^(oo)HCI=425 ohm^(-1)cm^(-1),A_(m)^(oo)NaCI=188 ohm^(-1)cm^(-1),A_(m)^(oo)CH_(3)COOHNa=96 ohm^(-1)cm^(-2)mol^(-1)`
Answer» Correct Answer - `333 ohm^(-1)cm^(2)mol^(-1)` `Lambda_(m(CH_(3)COOH))^(oo)=Lambda_(m(CH_(3)COONa))^(oo)+Lambda_(m(HCl))^(oo)-Lambda_(m(NaCl))^(oo)` `=(96.0+425.0-188.0)" ohm"^(-1)cm^(2)mol^(-1)=333" ohm"^(-1)cm^(2)mol^(-1)`.

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Calculte molar conductance at infinite dilution for acetic acid, given `A_(m)^(oo)HCI=425 ohm^(-1)cm^(-1),A_(m)^(oo)NaCI=188 ohm^(-1)cm^(-1),A_(m)^(oo)CH_(3)COOHNa=96 ohm^(-1)cm^(-2)mol^(-1)`

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