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calculte the total number of electrons present 1.4 g of dinitrogen gas. |
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Answer» Solution :Moles of `N_2 = (1.4)/28 = 0.05` No. of MOLECULES present `= 0.05 xx 6.022 xx 10^(23)` `:."No. of electrons present " = 0.05 xx 6.022 xx 10^(23) xx 14` `( :. 1 "MOLECULE of " N_2` CONTAINS 14 electrons) = `4.2154 xx 10^(23)` electrons |
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