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Calorific value of hydrogengas is - 143 kJ g^(-1). The standard enthalpy of formation of H_(2)Owill be |
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Answer» `- 143 kJ mol^(-1)` `:. `1 MOLE , i.e., 2 g `H_(2)` will produce heat`= 286kJ` This is also `Delta_(f)H^(@) ` for `H_(2)O`i.e. `Delta_(f)H^(@) = - 286 kJ mol^(-1)` |
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