1.

Calorific value of hydrogengas is - 143 kJ g^(-1). The standard enthalpy of formation of H_(2)Owill be

Answer»

`- 143 kJ mol^(-1)`
` + 143 kJ mol^(-1)`
` - 286 kJ mol^(-1)`
`+ 286kJ mol^(-1)`

Solution :Calorificvalue is the heat producedby COMBUSTION of 1 G of the FUEL, i.e., `H_(2)+(1)/(2)O_(2) rarr H_(2)O i.e., 1 g` of `H_(2)`on combustion producesheat `=143 kJ`
`:. `1 MOLE , i.e., 2 g `H_(2)` will produce heat`= 286kJ`
This is also `Delta_(f)H^(@) ` for `H_(2)O`i.e.
`Delta_(f)H^(@) = - 286 kJ mol^(-1)`


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