Can anyone solve the problems

1.	Can anyone solve the problems
Answer» Answer: Let the intercepts cut by the given line on the AXES be a and B. It is given that, a+b= 1....(1) and ab=−6....(2) On solving equation (1) and (2), we obtain a=3 and b=−2 or a=−2 and b=3 It is known that the equation of the line whose intercepts on the axes are a and b is a x + b y =1 or bx+ay−ab=0. case1: a=3 and b=−2 In this case the equation of the line is −2x+3y+6=0⇒2x−3y=6 case2: a=−2 and b=3 In this case the equation of line is 3x−2y+6=0⇒−3x+2y=6 Thus, the required equation of the lines are 2x−3y=6 and −3x+2y=6.

Answer»

Answer:

Let the intercepts cut by the given line on the AXES be a and B.

It is given that,

a+b= 1....(1)

and ab=−6....(2)

On solving equation (1) and (2), we obtain

a=3 and b=−2 or a=−2 and b=3

It is known that the equation of the line whose intercepts on the axes are a and b is

=1 or bx+ay−ab=0.

case1: a=3 and b=−2

In this case the equation of the line is −2x+3y+6=0⇒2x−3y=6

case2: a=−2 and b=3

In this case the equation of line is 3x−2y+6=0⇒−3x+2y=6

Thus, the required equation of the lines are 2x−3y=6 and −3x+2y=6.

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