Saved Bookmarks
| 1. |
Can plz anyone tell me the ans of 31 st question of exercise of chapter 2? Plzzzzz??? |
|
Answer» The electronic configuration is wrong.....check it out Unnati.....plz A) Total no. of electron in an atom for a value of n=2n^2For n= 4Total number of electron=2(4)^2The given element has a fully filled orbital as 1s^2 2s^2 2p^ 6 3s^2 3p^6 4s^2 3d^10Hence all the electron are pairedNumber of electron (having n= 4 nd m ↓s =-1/2) =16B) n= 3, l =0 indicate that the electron are present in the 3S orbitalTherefore the number of electron having an equal to 3 and l equal to zero is 2 Unknown I think it\'s wrong in this app |
|