Can plz anyone tell me the ans of 31 st question of exercise of chapte

1.	Can plz anyone tell me the ans of 31 st question of exercise of chapter 2? Plzzzzz???
Answer» The electronic configuration is wrong.....check it out Unnati.....plz<br>A) Total no. of electron in an atom for a value of n=2n^2For n= 4Total number of electron=2(4)^2The given element has a fully filled orbital as 1s^2 2s^2 2p^ 6 3s^2 3p^6 4s^2 3d^10Hence all the electron are pairedNumber of electron (having n= 4 nd m ↓s =-1/2) =16B) n= 3, l =0 indicate that the electron are present in the 3S orbitalTherefore the number of electron having an equal to 3 and l equal to zero is 2<br>Unknown<br>I think it\'s wrong in this app

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