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Can the theorem of isosceles triangle be proved by doing a different construction? |
Answer» Yes Construction: Draw seg AD ⊥ seg BC. Proof: In ∆ABD and ∆ACD, seg AB≅ seg AC [Given] ∠ADB ≅ ∠ADC [Each angle is of measure 90°] seg AD ≅ seg AD [Common side] ∴ ∆ABD ≅ ∆ACD [Hypotenuse side test] ∴ ∠ABD ≅ ∠ACD [c.a.c.t.] ∴ ∠ABC ≅ ∠ACB [B - D - C] |
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