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Car starts from rest and attains velocity of 20 m/s in 20 sec. the distance travelled in the car during this period is: *100 m200 m300 m400 m |
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Answer» the answer is 200mExplanation: GIVEN v = 20m/s, u = 0m/s, t = 20sNow we knowV = u+ at20 = 0 + 20A a = 1m/s squareTherefore,V square = u square + 2as20 square = 0 + 2 × 1 × S400 = 2sS = 400 ÷ 2S = 200mThe distance travelled by the car will be 200mPlease mark as the brainliest answer. |
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